Load the operator stack to call the function () in C ++

C ++ function call () can be overloaded for objects of class type. When you overload (), you are not creating a new way to call a function. Rather, you are creating an operator function that can be passed an arbitrary number of parameters.

The following example illustrates how to overload the operator to call the function () in C ++:

 #include using namespace std ; class KhoangCach { private : int met ; int centimet ; public : // phan khai bao cac constructor can thiet KhoangCach (){ met = 0 ; centimet = 0 ; } KhoangCach ( int m , int c ){ met = m ; centimet = c ; } // nap chong toan tu goi ham () KhoangCach operator ()( int x , int y , int z ) { KhoangCach K ; // bay gio, dat phep tinh bat ky K . met = x + y + 5 ; K . centimet = y - z + 20 ; return K ; } // Phuong thuc de hien thi khoang cach void hienthiKC () { cout << "nDo dai bang m la: " << met << "nVa do dai bang cm la: " << centimet << endl ; } }; int main () { KhoangCach K1 ( 24 , 36 ), K2 ; cout << "Khoang cach dau tien la: " ; K1 . hienthiKC (); K2 = K1 ( 15 , 15 , 15 ); // trieu hoi toan tu () cout << "n--------------------------n" ; cout << "Khoang cach thu hai la: " ; K2 . hienthiKC (); return 0 ; } 

Compiling and running the above C ++ program will produce the following results:

According to Tutorialspoint

Previous lesson: Load the assignment operator stack in C ++

Next lesson: Load the subscript operator [] in C ++