Returns the pointer from the function in C ++

As we have seen how C ++ allows to return an array from a function, similarly, C ++ allows you to return a pointer from a function. To do this, you must declare a function that returns a pointer as follows:

 int *  tenHam () { . . . } 

The second thing to keep in mind is that it is not a good idea to return the address of a local variable to the periphery of a function, so you will have to define a local variable as a static variable.

Now suppose the following function will generate 10 random numbers and return them using an array name that represents a pointer, for example, the first address of the first array element.

 #include #include #include using namespace  std ; // phan dinh nghia ham de tao va tra ve cac so ngau nhien. int *  soNgauNhien ( ) { static int  r [ 10 ];  srand ( ( unsigned ) time (  NULL  ) ); for ( int  i  = 0 ;  i  < 10 ; ++ i ) {  r [ i ] =  rand ();  cout  <<  r [ i ] <<  endl ; } return  r ; } // ham main de goi phan dinh nghia ham tren. int  main  () { // mot con tro tro toi mot so nguyen. int * p ;  p  =  soNgauNhien (); for ( int  i  = 0 ;  i  < 10 ;  i ++ ) {  cout  << "Gia tri cua *(p + " <<  i  << ") : " ;  cout  << *( p  +  i ) <<  endl ; } return 0 ; } 

Running the above C ++ program will produce the following results:

According to Tutorialspoint

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