Min () function in Python
The built-in min () function in Python returns the smallest element in an iterable or smallest of passed parameters.
If the values are strings, they will compare alphabetically.
So, how does the syntax of min () function work, what parameters and how does it work? Invites you to read the track.

The syntax of min () function in Python
The min () function in Python has two forms:
min(iterable, *iterables[,key, default])
Or:
min(item1, item2, *item[, key])
Parameters of min function ()
The min () function works with two types of parameters corresponding to the two syntaxes mentioned above:
1. min(iterable, *iterables[, key, default])
iterable
: Required. The tuples, string, set, dictionary or iterator objects that you need to find the smallest element in.*iterables
: Optional. The smallest Iterable will be returned.key
: Optional. Key function, where the iterable goes through. Comparisons are made based on the results returned after passing the key function.default
: Optional. The default value when iterable is empty.
2. min(item1, item2, *item[, key])
item1
,item2
: Required. Object to compare, can be number, string .*item
: Optional. Other objects for comparison.
Min () function in Python Picture 2 At least two objects are needed to make comparisons with the min () function.
key
: Optional. Key function, where items pass. The comparison is performed on the result returned after passing the key function.
Return value from min ()
The min () function returns different results corresponding to the two types as above:
1. min(iterable, *iterables[, key, default])
2. min(item1, item2, *item[, key])
Example 1: Find the smallest element in the number passed
# su dung min(item1, item2, *item) print('So nho nhat la:', min(1, 3, 2, 5, 4)) # su dung min(iterable) num = [1, 3, 2, 8, 5, 10, 6] print('So nho nhat la:', min(num))
Run the program, the result is:
So nho nhat la: 1 So nho nhat la: 2
Example 2: Find the number that has the smallest number of digits using the key function
def sumDigit(num): sum = 0 while(num): sum += num % 10 num = int(num / 10) return sum # su dung min(item1, item2, *item, key) print('Ket qua nho nhat la:', min(100, 321, 267, 59, 40, key=sumDigit)) # su dung min(iterable, key) num = [15, 300, 2700, 821, 52, 10, 6] print('Ket qua nho nhat la:', min(num, key=sumDigit))
The return output is:
Ket qua nho nhat la: 100 Ket qua nho nhat la: 10
In this example, the parameters or each element in the iterable parameter are passed in turn to sumDigit()
to get the result that the number has the smallest sum of digits.
Example 3: Find the list with the smallest length using the key function
num = [15, 300, 2700, 821] num1 = [12, 2] num2 = [34, 567, 78] # su dung min(iterable, *iterables, key) print('List ngan nhat la:', min(num, num1, num2, key=len))
Results returned:
List ngan nhat la: [12, 2]
In the above program, iterable num, num1 and num2 passed into the key function are built-in len () functions in Python. The result is iterable, and the min () function will iterable with the smallest length.
See also: Built-in Python functions
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