FROM bang1
INNER JOIN bang2
ON bang1.cot_chung = bang2.cot_chung;
Parameters :
Suppose the two tables are NHANVIEN and TIENTHUONG with the following records:
Table 1: NHANVIEN
+----+----------+-----+-----------+----------+ | ID | TEN |TUOI | DIACHI | LUONG | +----+----------+-----+-----------+----------+ | 1 | Thanh | 32 | Haiphong | 2000.00 | | 2 | Loan | 25 | Hanoi | 1500.00 | | 3 | Nga | 23 | Hanam | 2000.00 | | 4 | Manh | 25 | Hue | 6500.00 | | 5 | Huy | 27 | Hatinh | 8500.00 | | 6 | Cao | 22 | HCM | 4500.00 | | 7 | Lam | 24 | Hanoi | 10000.00 | +----+----------+-----+-----------+----------+
Table 2: TIENTHUONG
+-----+---------------------+-------------+--------+ |TT_ID| NGAY | NHANVIEN_ID | SOTIEN | +-----+---------------------+-------------+--------+ | 102 | 2019-01-08 00:00:00 | 3 | 3000 | | 100 | 2019-01-08 00:00:00 | 3 | 1500 | | 101 | 2019-02-20 00:00:00 | 2 | 1560 | | 103 | 2018-12-20 00:00:00 | 4 | 2060 | +-----+---------------------+-------------+--------+
Now, let's join these two tables using INNER JOIN as follows:
SQL> SELECT ID, TEN, SOTIEN, NGAY
FROM NHANVIEN
INNER JOIN TIENTHUONG
ON NHANVIEN.ID = TIENTHUONG.NHANVIEN_ID;
The result is:
+----+----------+--------+---------------------+ | ID | TEN | SOTIEN | NGAY | +----+----------+--------+---------------------+ | 3 | Nga | 3000 | 2019-01-08 00:00:00 | | 3 | Nga | 1500 | 2019-01-08 00:00:00 | | 2 | Loan | 1560 | 2019-02-20 00:00:00 | | 4 | Manh | 2060 | 2018-12-20 00:00:00 | +----+----------+--------+---------------------+
See more types of JOIN: