JAVA test on P6
Multiple choice questions about Java programming give you useful knowledge. If you love Java programming, don't skip the series of interesting tests below by Network Administrator.
-
Question 1. Which line is wrong?
1. int i = 0;
2. due to {
3. i + = 1;
4.} while (i == 0);
5. System.out.println ('i =' + i);-
first
-
2 and 3
-
4
-
No wrong lines
-
-
Question 2. s is the result of how much when executing the command block?
int i = 0;
int s = 0;
for (;;) {
if i == 3 break;
s = s + i;
i ++;
}-
6
-
3
-
Program reported an error
-
0
-
-
Question 3. In what line is the program wrong?
1. int i = 0;
2. int s = 0;
3. for (;;) {
4. if i == 3 break;
5. s = s + i;
6. i ++;
7.}-
1 and 2
-
4
-
6
-
No wrong lines
-
-
Question 4. What is the result of the program?
BreakDemo class {
public static void main (String [] args) {
int [] arrayOfInts = {32, 87, 3, 589, 12, 1076, 2000, 8, 622, 127};
int searchFor = 12;
int i;
boolean fountIt = false;
for (i = 0; i
if (arrayOfInts [i] == searchFor) {
fountIt = true;
break;
}
}
if (fountIt) {
System.out.println ('Found' + searchFor + 'at index' + i);
} else
System.out.println (searchFor + 'not in the array');
}
}-
12 không phải trong mảng
-
Found 12 at index 4
-
Program error
-
- Found it
-
-
Question 5. Which line is wrong?
1. BreakDemo class {
2. public static void main (String [] args) {
3. int [] arrayOfInts = {32, 87, 3, 589, 12, 1076, 2000, 8, 622, 127};
4. int searchFor = 12;
5. int i;
6. boolean fountIt = false;
7. for (i = 0; i
8. if (arrayOfInts [i] == searchFor) {
9. fountIt = true;
10. break;
11.}
twelfth. }
13. if (fountIt) {
14. System.out.println ('Found' + searchFor + 'at index' + i);
15.} else
16. System.out.println (searchFor + 'not in the array');
17.}
18.}-
2 and 6
-
- 3 and 11, 15
-
- 5, 7, 9
-
No programs are wrong
-
-
Question 6. What does the program do?
BreakDemo class {
public static void main (String [] args) {
int [] arrayOfInts = {32, 87, 3, 589, 12, 1076, 2000, 8, 622, 127};
int searchFor = 12;
int i;
boolean fountIt = false;
for (i = 0; iif (arrayOfInts [i] == searchFor) {
fountIt = true;
break;
}
}
if (fountIt) {
System.out.println ('Found' + searchFor + 'at index' + i);
} else
System.out.println (searchFor + 'not in the array');
}
}-
Find an element in the array
-
- Compare array elements together.
-
Calculate the total array.
-
All answers are wrong
-
-
Question 7. What does the following program do?
class ContinueDemo {
public static void main (String [] args) {
String searchMe = 'peter piper picked up a peck of pickled peppers';
int max = searchMe.length ();
int numPs = 0;
for (int i = 0; i
if (searchMe.charAt (i)! = 'p') continue;
numPs ++;
}
System.out.println ('Found' + numPs + 'p's in the string.');
}
}-
Count the letter p in the character string
-
Find out if the p is in front of the letter i in the string
-
Search for letter p in the string
-
All is wrong
-
-
Question 8. What is the result of the following program?
class ContinueDemo {
public static void main (String [] args) {
String searchMe = 'peter piper picked up a peck of pickled peppers';
int max = searchMe.length ();
int numPs = 0;
for (int i = 0; i
if (searchMe.charAt (i)! = 'p')
tiếp tục;
numPs ++;
}
System.out.println ('Found' + numPs + 'p's in the string.');
}
}-
- Found 9 p's in the string.
-
Found 8 p's in the string.
-
Found 10 p's in the string.
-
There is no right answer.
-
-
Question 9. What is the result of the following program?
class ContinueDemo {
public static void main (String [] args) {
String searchMe = 'peter piper picked up a peck of pickled pepers';
int max = searchMe.length ();
int numPs = 0;
for (int i = 0; i
if (searchMe.charAt (i)! = 'p')
tiếp tục;
numPs ++;
}
System.out.println ('Found' + numPs + 'p's in the string.');
}
}-
Found 9 p's in the string.
-
Found 8 p's in the string.
-
Found 10 p's in the string.
-
There is no right answer.
-
-
Question 10. Which method of the String class returns the index of the child string that appears first in the char character string '
-
concat ()
-
charAt ()
-
indexOf ()
-
There is no right answer.
-
Was this article helpful?
Your feedback helps us improve.

Reader Comments 0
Sign in with email or Google to join the discussion.