Python Locals ()() Function

This guide covers python locals ()() function with practical context and easy-to-follow details. Use it to understand the subject and apply the information confidently.

Python Syntax of Locals ()() Function

locals()

• There are no parameters and arguments in the function.

Value Returned from Locals

The locals () function Updates and returns the dictionary associated with the current local symbol table.

Example: How Does the Locals ()() Function Work?

locals()

Run the program, the result is:

{'In': ['', 'locals()'],
 'Out': {},
 '_': '',
 '__': '',
 '___': '',
 '__builtin__': , '__builtin__': ,
 '__builtins__': , '__builtins__': ,
 '__name__': '__main__',
 '_dh': ['/tmp/tmp98r7zamj'],
 '_i': '',
 '_i1': 'locals()',
 '_ih': ['', 'locals()'],
 '_ii': '',
 '_iii': '',
 '_oh': {},
 '_sh': , '_sh': ,
 'exit': ,
 'get_ipython': >,
 'quit': }

Example 2: How Does Locals ()() Work in Local Scope?

def localsNotPresent():
 return locals()

def localsPresent():
 present = True
 return locals()

print('localsNotPresent:', localsNotPresent())
print('localsPresent:', localsPresent())

Running the program results in:

localsNotPresent: {}
localsPresent: {'present': True}

Example 3: Update Values with Locals ()()

def localsPresent():
 present = True
 print(present)
 locals()['present'] = False;
 print(present)

localsPresent()

True
True

Unlike the globals dictionary that can change the value of a variable, locals do not change information inside the local namespace.

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