The Function Memcpy ()() in C

This guide covers the function memcpy ()() in c with practical context and easy-to-follow details. Use it to understand the subject and apply the information confidently.

Declare the Function Memcpy ()() in C

Below is the declaration for memcpy () in C:

 void * memcpy ( void * str1 , const void * str2 , size_t n ) 

Parameters

Str1 - This is the pointer to the destination array, where the content to be copied, cast into a pointer of type void *.

Str2 - This is the pointer to the data source to copy, cast into a pointer of type void *.

n - This is the number of bytes to be copied.

Returns the Value

This function returns a pointer to the destination string, str1.

For Example

The following program C illustrates the usage of memcpy () in C:

 #include #include struct { char name [ 40 ]; int age ; } person , person_copy ; int main () { char myname [] = "Nguyen Hoang Nam" ; /* su dung ham memcpy de sao chep chuoi: */ memcpy ( person . name , myname , strlen ( myname )+ 1 ); person . age = 46 ; /* su dung ham memcpy de sao chep struct: */ memcpy ( & person_copy , & person , sizeof ( person ) ); printf ( "person_copy = %s, %d n" , person_copy . name , person_copy . age ); return 0 ; } 

Compiling and running the above C program will result:

According to Tutorialspoint

Previous article: Function memcmp () in C

Next lesson: memmove function in C